SOLUTION: How much of an alloy that is 30% copper should be mixed with 200 ounces of an alloy that is 70 % copper in order to get an alloy that is 50 % copper this is what I came up with.

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Question 855701: How much of an alloy that is 30% copper should be mixed with 200 ounces of an alloy that is 70 % copper in order to get an alloy that is 50 % copper
this is what I came up with...is this right
x(30%)+(200)(70%)=200+x(50)
.3x+140=100+.5x
40=.2x
x=200

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
x how much to add or use



Your initial setup seems good. Maybe you let the switch to decimal fractions confuse you?




, and in fact this works as correct when tried as a check in our original equation.

(Seemed strange to me also, ...until examining the AVERAGE of 30 and 70. Their middle value IS 50.)

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