SOLUTION: There was a jar of cookies. Katie ate half the cookies. Myron ate a third of what was left in the jar. Gina decided to take a fourth of the remaining cookies. Then nancy came and t
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-> SOLUTION: There was a jar of cookies. Katie ate half the cookies. Myron ate a third of what was left in the jar. Gina decided to take a fourth of the remaining cookies. Then nancy came and t
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Question 809238: There was a jar of cookies. Katie ate half the cookies. Myron ate a third of what was left in the jar. Gina decided to take a fourth of the remaining cookies. Then nancy came and took a cookie to munch on. When chelsea look at the jar she saw two cookies left. How many cookies were there in the jar to begin with? Found 2 solutions by TimothyLamb, josgarithmetic:Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! C
k = C/2
m = C/6
before gina: r
g = (1/4)r
g = (C - k - m)/4
after gina: a = 3
r = (1/4)r + 3
(4/4)r - (1/4)r = 3
(3/4)r = 3
r = 4
before gina: r = 4
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g = 1
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after myron: r = 4
r = (1/3)r + 4
(3/3)r - (1/3)r = 4
(2/3)r = 4
r = 6
before myron: r = 6
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m = 2
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after katie : r = 6
r = (1/2)r + 6
(2/2)r - (1/2)r = 6
(1/2)r = 6
r = 12
before katie: r = 12
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k = 6
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Answer:
C = 12
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Katie: .
Myron: .
Gina: .
Nancy and Chelsea: 3 cookies. Think about these two people a bit before continuing.
If J = the number of cookies originally in the jar, then
The best denomination to use is forty-eighths, or as (1/48). Rewrite the entire expression for the factor on J in forty-eighths.
(So much text to use... so abbreviating... easier on paper....)
The simplified equation then is , eighteen cookies were initially in the jar.
(