SOLUTION: The ratio fo red jelly beans to yellow jelly beans in a dish is 3:4. If Greg eats 3 red jelly beans and 6 yellow ones, the ratio is 4:5. How many jelly beans were originally in t

Question 773272: The ratio fo red jelly beans to yellow jelly beans in a dish is 3:4. If Greg eats 3 red jelly beans and 6 yellow ones, the ratio is 4:5. How many jelly beans were originally in the dish?
3/4 = RJB/YJB
4rjb = 3yjb
4(rjb-3) = 3(yjb-6)
Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website!
You are asking if you are solving correctly.
Let r = how many red jelly beans
let y = how many yellow jelly beans

Originally,

Ate 3 red beans so now r-3 red beans in the dish;
Ate 6 yellow beans, so y-6 yellow beans still in the jar.

Two equations in the two unknowns r and y.
ORIGINAL EQUATION

EATEN EQUATION

SYSTEM TO SOLVE MAY BE:
and
Multiply by 3 for eaten equation, multiply by 4 for original equation
in these forms, and obtain,...
and .
Subtracting the "0" equation from the "-30" equation, obtain:

and then this means from original ratio,
____________________________________________________________
Originally 30 red jelly beans and 40 yellow jelly beans
____________________________________________________________
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