SOLUTION: Solve for x (1) x-1/4-2x-3/3=-1/12 (2) 2/6x-19=3/2x-11 (3) 2x+3/3x+4=7/10

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Question 763092: Solve for x

(1) x-1/4-2x-3/3=-1/12
(2) 2/6x-19=3/2x-11
(3) 2x+3/3x+4=7/10
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Solve for x

(1) x-1/4-2x-3/3=-1/12
x - 1/4 - 2x - 1 = -1/12\
-x - 5/4 = -1/12
-x = -1/12 + 5/4 = -1/12 + 15/12
-x = 14/12
x = -7/6
======================
(2) 2/6x-19=3/2x-11
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Multiply thru by 6x
2 - 19*6x = 9 - 11*6x
2 - 114x = 9 - 66x
2 = 9 + 48x
48x = -7
x = -7/48
=============================
(3) 2x+3/3x+4=7/10
2x + 1/x + 4 = 7/10
2x + 1/x = -33/10
AMP Parsing Error of [2x^2 + + 33x/10 - 1 = 0]: Invalid expression '+33\x/10-1=0': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. .
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=18.89 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 0.261565690605037, -1.91156569060504. Here's your graph:

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