SOLUTION: In a play, 30% of the audience are female. If there are 500 more males than females, what is the total audience?

Question 755453: In a play, 30% of the audience are female. If there are 500 more males than females, what is the total audience?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In a play, 30% of the audience are female. If there are 500 more males than females, what is the total audience?
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Equations:
m = f + 500
f = 0.3(m+f)
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Substitue for "m" and solve for "f"
f = 0.3(f+500) + 0.3f
----
10f = 3f + 1500 + 3f
4f = 1500
f = 375 (# of females)
m = f + 500 = 875 (# of males)
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Cheers,
Stan H.
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