SOLUTION: How much 60% disinfectant solution must be mixed with a 80% disinfectant solution to produce 25 gallons of a 72% disinfectant solution?
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Question 721073: How much 60% disinfectant solution must be mixed with a 80% disinfectant solution to produce 25 gallons of a 72% disinfectant solution?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How much 60% disinfectant solution must be mixed with a 80% disinfectant solution to produce 25 gallons of a 72% disinfectant solution?
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Equation:
active + active = active
0.60x + 0.80(25-x) = 0.72*25
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Multiply thru by 100 to get:
60x + 80*25 - 80x = 72*25
-20x = -8*25
x = 10 gallons (amt. of 60% solution needed)
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Cheers,
Stan H.
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