SOLUTION: a dishonest jeweler claims that the articles he sells are made of pure gold but actualy he mixes silver with gold. pure gold weights 19gm/cm^3
and silver 8 gm/cm^3. one cm^3 of th
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Question 696353: a dishonest jeweler claims that the articles he sells are made of pure gold but actualy he mixes silver with gold. pure gold weights 19gm/cm^3
and silver 8 gm/cm^3. one cm^3 of the articles sold by the jeweler weighs 18gm/cm^3. the ratio of weight of gold an d silver he mixes is??
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = cm3 of gold in jewelers 1 cm^3
Let = cm3 of silver in jewelers 1 cm^3
(1)
Note that in terms of units, this is
( gm / cm3 )x( cm3 ) + ( gm / cm3 ) = ( gm )
So I have ( gm ) = ( gm )
---------------------
Also,
(2)
( cm3 ) + ( cm3 ) = ( cm3 )
-----------------------
Multiply both sides of (2) by
and subtract (2) from (1)
(1)
(2)
and, since
(2)
(2)
---------------
There is 10/11 cm3 of gold in jewelers 1 cm^3
There is 1/11 cm3 of silver in jewelers 1 cm^3
The weight of gold in 10/11 cm3 is
The weight of silver in 1/11 cm3 is
( weight of gold ) / ( weight of silver ) =
---------------------------------------
( weight of gold ) / ( weight of silver ) = 23.75
---------------------------------------
check answer:
OK
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