SOLUTION: kindly show me the answer and solution to this problem.....divide 56 into two parts. If the larger number exceeds twice the smaller number by 5, find the numbers....i hope that you

Question 66762: kindly show me the answer and solution to this problem.....divide 56 into two parts. If the larger number exceeds twice the smaller number by 5, find the numbers....i hope that you can show me the step-by-step solution and the answer
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
kindly show me the answer and solution to this problem.....divide 56 into two parts.
HENCE THEY ARE X AND 56-X SAY.
If the larger number exceeds twice the smaller number by 5,
IF X IS LARGER NUMBER ,THEN SMALLER NUMBER=56-X
TWICE IT = 2(56-X)=112-2X...........5 MORE.....= 112-2X+5=117-2X
HENCE
X=117-2X
3X=117
X=39
find the numbers....
THE NUMBERS ARE 39 AND 56-39=17
i hope that you can show me the step-by-step solution and the answer
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