SOLUTION: A chemist 80 mil of 25% chemical solution. he only has a 50% chemical solution and a 10% chemical solution. find how many ml of each he should mix to get the desired solution.

Question 659460: A chemist 80 mil of 25% chemical solution. he only has a 50% chemical solution and a 10% chemical solution. find how many ml of each he should mix to get the desired solution.
Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = ml of 50% solution needed
Let = ml of 10% solution needed
given:
(1)
(2)
---------------------------
(2)
(2)
(2)
Subtract (1) from (2)
(2)
(1)

and, since
(1)
(1)
(1)
30 ml of 50% solution are needed
50 ml of 10% solution are needed
check:
(2)
(2)
(2)
(2)
OK

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A chemist 80 mil of 25% chemical solution. he only has a 50% chemical solution and a 10% chemical
-------
Equation:
active + active = active
0.50x + 0.10(80-x) = 0.25*80
----
Multiply thru by 100 to get:
50x + 10*80 - 10x = 25*80
40x = 15*80
x = 30 ml (amt. of 50% solution needed)
-------
80-x = 70 ml (amt. of 10% solution needed)
========================
Cheers,
Stan H.
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