SOLUTION: REDUCING THE SIZE OF A CANDY BAR
a jumbo chocolate bar with a rectangular shape measures 12 centimeters in length, 7 centimeters in width, and 3 centimeters in thickness. Due
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Question 649546: REDUCING THE SIZE OF A CANDY BAR
a jumbo chocolate bar with a rectangular shape measures 12 centimeters in length, 7 centimeters in width, and 3 centimeters in thickness. Due to escalating costs in cocoa, management decides to reduce the volume of the bar by 20%. too accomplish this reduction, management decides that the new bar should have the same 3 centimeters in thickness, but the length and width of each should be reduced an equal number of centimeters. what should be the dimensions of the new candy bar?
i know that volume=LWH which would then be v=(12)(7)(3) so v=252 cm^3 and then i would multiply by 20% to get 50.4 cm^3 then subtract to get 201.6 cm^3
then i would set that as 201.6 cm^3 = (3)(L)(W) divide each side by 3 to get 67.2 cm^3=(L)(W)
Thats where I get stuck... Thanks!
Answer by MathTherapy(10556) (Show Source): You can put this solution on YOUR website!
REDUCING THE SIZE OF A CANDY BAR
a jumbo chocolate bar with a rectangular shape measures 12 centimeters in length, 7 centimeters in width, and 3 centimeters in thickness. Due to escalating costs in cocoa, management decides to reduce the volume of the bar by 20%. too accomplish this reduction, management decides that the new bar should have the same 3 centimeters in thickness, but the length and width of each should be reduced an equal number of centimeters. what should be the dimensions of the new candy bar?
i know that volume=LWH which would then be v=(12)(7)(3) so v=252 cm^3 and then i would multiply by 20% to get 50.4 cm^3 then subtract to get 201.6 cm^3
then i would set that as 201.6 cm^3 = (3)(L)(W) divide each side by 3 to get 67.2 cm^3=(L)(W)
Thats where I get stuck... Thanks!
Volume of candy bar before reduction = 12 * 7 * 3, or 252
Reduction by 20% results in a reduced candy bar volume of: .8(252), or 201.6
Let length of reduced bar be L
Then width = L also
Since volume of reduced bar = 201.6, and with thickness being the same (3 cm), then we have: L(L)(3) = 201.6
---- This is where you got stuck, but it should be L * L, since L = W
L, or length of reduced bar = = 8.2 (rounded). Width = 8.2 (rounded) also.
Dimensions of new candy bar =
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