SOLUTION: The question: A collection of marbles has been divided into three different sets. The middle-sized set is two times the size of the smallest set, and the largest set is three time

Question 63313: The question: A collection of marbles has been divided into three different sets. The middle-sized set is two times the size of the smallest set, and the largest set is three times as large as the middle-sized set. What percent describes each part of the total marble collection?
Can this problem be answered with the information given?
Found 2 solutions by ptaylor, stanbon:
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Yes. This problem can be answered with the information given and here's how:
We'll let x=smallest set
then 2x=middle-sized set
and 3(2x)=largest set
Now if we let t=total marble collection, then we have:
x+2x+3(2x)=t or
x+2x+6x=t and
9x=t
x=(1/9)t or put another way the smallest set is 11.11% of the total (t) and
2x=(2/9)t or the middle-sized set is 22.22% of the total (t) and finally
6x=(6/9)t or the largest set is 66.67% if the total (t)
Hope this helps and have a happy holiday season!!!!!---ptaylor

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Let the three parts be A,B,C and let A Then A=3B and B=2C, so A=6C
EQUATION: A+B+C=100%
A+(1/3)A+(1/6)A=100%
6A+2A+A=100%
A:B:C = 6x:2x:x
9x=100%
x=11.1111..%
A=6x=66.6666...%
B=2x=22.2222...%
C=x=11.11111...%
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Cheers,
Stan H.
C=
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