SOLUTION: How many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 10% antifreeze to get a mixture that is 50% difference?
Algebra.Com
Question 507450: How many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 10% antifreeze to get a mixture that is 50% difference?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
How many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 10% antifreeze to get a mixture that is 50% difference?
.
Let x = amount (gallons) of 60% antifreeze
then
.60x + .10(90) = .50(x+90)
.60x + 9 = .50x+45
.10x + 9 = 45
.10x = 36
x = 360 gallons
RELATED QUESTIONS
how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 10%... (answered by stanbon)
How many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 10%... (answered by nshah11)
how many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 30%... (answered by stanbon)
how many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 30%... (answered by stanbon)
How many gallons of a 90% antifreeze solution must be mixed with 60 gallons of 25%... (answered by josgarithmetic)
How many gallons of a 90% antifreeze solution must be mixed with 60% gallons of 15%... (answered by jorel1380)
How many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 25%... (answered by Theo)
How many gallons of 70% antifreeze solution must be mixed with 90 gallons of 25%... (answered by oberobic)
how many gallons of 90 percent antifreeze solution must be mixed with 100 gallons of 10... (answered by josmiceli)