Since the ratio is 4:3, add them and get 7, so that means

that 4/7ths of them are males and 3/7ths are females, and that

there must be a multiple of 7 students, otherwise we'd get a

fraction when we took those fractions of them, and we can't have 

a fraction of a student.



The only choice among those 5 that 7 won't divide evenly into is 30.

So the answer is D)



Edwin
 



 

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