SOLUTION: The acoustical intensity, I, of a sound wave is proportional to the square of the pressure amplitude, P, and inversely proportional to the velocity, v, of the wave. If I=0.6W/m^2 f

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Question 436849: The acoustical intensity, I, of a sound wave is proportional to the square of the pressure amplitude, P, and inversely proportional to the velocity, v, of the wave. If I=0.6W/m^2 for P=30.0Pa and v=150m/s, find v if P=50 Pa and I=2.4W/m^2.
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Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
The acoustical intensity, I, of a sound wave is proportional to the square of
the pressure amplitude, P, and inversely proportional to the velocity, v, of the wave.
If I=0.6W/m^2 for P=30.0Pa and v=150m/s, find v if P=50 Pa and I=2.4W/m^2.
:
From the given information we can write a formula:
I = , where k is the constant of variation
:
Using the given values, find k:
"If I=0.6W/m^2 for P=30.0Pa and v=150m/s
:
.6 =
150*.6 = 900k
90 = 900k
k =
k = .1 the constant of variation
:
We can write the formula
I =
:
"find v if P=50 Pa and I=2.4W/m^2."
2.4 =
2.4v = .1*2500
v =
v = 104.167 m/sec

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