SOLUTION: 12 m/sThe energy, E, released when an object is stopped varies directly as the square of its velocity, v. If an object releases 600kj of energy when stopped from a velocity of 5m/s

Question 436178: 12 m/sThe energy, E, released when an object is stopped varies directly as the square of its velocity, v. If an object releases 600kj of energy when stopped from a velocity of 5m/s. How much energy is released when it is stopped from a speed of 12m/s?
Found 2 solutions by stanbon, htmentor:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The energy, E, released when an object is stopped varies directly as the square of its velocity, v. If an object releases 600kj of energy when stopped from a velocity of 5m/s. How much energy is released when it is stopped from a speed of 12m/s?
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E = kv^2
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Solve for "k" using "If an object releases 600kj of energy when stopped from a velocity of 5m/s".
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600 = k*5^2
k = 24
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Equation:
E = 24*v^2
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How much energy is released when it is stopped from a speed of 12m/s?
E = 24*12^2
E = 3456kj
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Cheers,
Stan H.
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Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
Since the energy varies directly as the square of the velocity, we can write:
E = kv^2
where k is a constant
Given: 600 kJ released when v = 5 m/s.
Use this information to find k:
600 kJ = k(5 m/s)^2
k = 600/25 = 24 kJ*s^2/m^2
So, the energy released when v = 12 m/s is:
E = 24(12)^2 = 3456 kJ
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