SOLUTION: Please help, I can't seem to figure this one out!
R(x)=200x-0.01x^2
C(x)= 38x+0.01x^2
Producing and selling how many units will give maximum profit?
What is the maximum p
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-> SOLUTION: Please help, I can't seem to figure this one out!
R(x)=200x-0.01x^2
C(x)= 38x+0.01x^2
Producing and selling how many units will give maximum profit?
What is the maximum p
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Question 435974: Please help, I can't seem to figure this one out!
R(x)=200x-0.01x^2
C(x)= 38x+0.01x^2
Producing and selling how many units will give maximum profit?
What is the maximum possible profit?
I tried P(x)=R(x)-C(x) but I can't get it to a quadratic equation I can solve. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! R(x)=200x-0.01x^2
C(x)= 38x+0.01x^2
Producing and selling how many units will give maximum profit?
What is the maximum possible profit?
I tried P(x)=R(x)-C(x) but I can't get it to a quadratic equation I can solve.
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P(x) = (200x-0.01x^2)-(38x+0.01x^2)
= 162x-0.02x^2
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Cheers,
Stan H.
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