SOLUTION: I'm having trouble setting up the following problem:
The ratio of ducks to geese was 5 to 4. Four times the number of ducks was 40 greater than 3 times the number of geese. How ma
Algebra.Com
Question 389142: I'm having trouble setting up the following problem:
The ratio of ducks to geese was 5 to 4. Four times the number of ducks was 40 greater than 3 times the number of geese. How many of each kind of fowl were present?
Please help -- I've drawn a blank.
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
d / g = 5 / 4 ___ 4d = 5g
4d - 40 = 3g
substituting ___ (5g) - 40 = 3g ___ 2g = 40 ___ g = 20
substituting ___ 4d = 5(20) ___ d = 25
RELATED QUESTIONS
3 chickens and a duck sold for as much as 2 geese;1chicken, 2 ducks, and 3 geese were... (answered by josmiceli)
What is the fewest number of ducks if there are two ducks before a duck, two ducks behind (answered by richard1234)
Hi My little cousin needs help with this homework problem, I tried helping her but I... (answered by checkley77)
A carnival games uses plastic ducks for players to pick. If people chose one with a... (answered by tvandenberg)
I'm having trouble with setting up the equation of this word problem:
A rectangle... (answered by MathLover1)
Hi
The ratio of ducks to chickens to cows is 12 to 9 to 2 respectively. If 15 chickens... (answered by math_tutor2020)
I'm having trouble setting up the equation for the following problem:
A plane flies... (answered by josgarithmetic,macston)
A normal duck has two legs.A lame duck has one leg.A sitting duck has no legs.There are... (answered by Theo)
The ratio of fish to ducks was 5 to 2. There are 28 in all, how many were... (answered by stanbon)