SOLUTION: A chemist is mixing a 11% acidic solution with a 6% acidic solution to obtain 600 mL of an 8% acidic solution. How much of each must he have?

Question 368329: A chemist is mixing a 11% acidic solution with a 6% acidic solution to obtain 600 mL of an 8% acidic solution. How much of each must he have?
Found 2 solutions by Fombitz, amoresroy:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Let A be the amount of 11% acidic solution, B the amount of 6% acidic solution
1.

2.
Multiply eq. 1 by (-6) and add to eq. 2,

ml
Then from eq. 1,

ml

Answer by amoresroy(361) (Show Source): You can put this solution on YOUR website!
A chemist is mixing a 11% acidic solution with a 6% acidic solution to obtain 600 mL of an 8% acidic solution. How much of each must he have?
Let x = the amount of 11% acidic solution
600-x = the amount of 6% acidic solution
.11x + .06(600-x) = .08(600)
.11x + 36 - .06x = 48
.05x = 12
x = 240
600 - x = 360
The chemist must have 240 mL of 11% acidic solution and 360 mL of 6% acidic solution.
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