SOLUTION: Use the quadratic formula to solve the equation for x in terms of y.? 2x^2 + 9xy -5 - y^2 = 0 This is what I did: (2)x^2 + (9y)x + (-y^2-5) = 0 -9y +/- square root: 9y^2 -4(2

Question 342241: Use the quadratic formula to solve the equation for x in terms of y.?
2x^2 + 9xy -5 - y^2 = 0
This is what I did:
(2)x^2 + (9y)x + (-y^2-5) = 0
-9y +/- square root: 9y^2 -4(2)(-y^2-5) / 4
-9y +/- square root: 9y^2 + 8y^2 +40/ 4
-9y +/- square root : 17y^2 +40/ 4
Why is this answer wrong? Please explain. Thanks!!
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

You didn't square the term correctly.

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