SOLUTION: Please ! help me about this three word problems. I ca not work out. (1) The denominator of a fraction is three more than the numerator. If the numerator is doubled and the d

Question 33723This question is from textbook ratios and fractions
: Please ! help me about this three word problems. I ca not work out.
(1) The denominator of a fraction is three more than the numerator. If the numerator is doubled and the denominator is increased by nine, the resulting fraction is equal to �. What is the original fraction?
From yours poor student
This question is from textbook ratios and fractions

Answer by mukhopadhyay(490) (Show Source): You can put this solution on YOUR website!
Let the numerator be x
The denominator = x+3
The fraction is now x/(x+3);
Numerator doubled and the denominator is increased by nine makes the fraction:
2x/(x+9) = 1/2
=> 4x = (x+9)
=> x = 3
The original fraction is 3/6 = 1/2
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