SOLUTION: You randomly choose a piece of hard candy from a jar containing 5 peppermint, 10 butterscotch, and 7 cinnamon candies. You decide that you don't want the piece that you chose, so y
Question 295405: You randomly choose a piece of hard candy from a jar containing 5 peppermint, 10 butterscotch, and 7 cinnamon candies. You decide that you don't want the piece that you chose, so you put it back and randomly choose another piece. Find the probability that you choose a cinnamon candy first and a butterscotch candy second. Thanks! Answer by Edwin McCravy(20060) (Show Source): You can put this solution on YOUR website!
There are 22 pieces of candy in the jar.
Since "AND" means "multiply",
P(cinnamon first AND butterscotch second)
=
Edwin