SOLUTION: Con all had a box of 36 candy bars to sell for a class fundraiser. He sold 10 of the bars on his own, and his mother sold half of the remaining bars to her coworkers. If no other b

Algebra ->  Algebra  -> Percentage-and-ratio-word-problems -> SOLUTION: Con all had a box of 36 candy bars to sell for a class fundraiser. He sold 10 of the bars on his own, and his mother sold half of the remaining bars to her coworkers. If no other b      Log On

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 Question 273607: Con all had a box of 36 candy bars to sell for a class fundraiser. He sold 10 of the bars on his own, and his mother sold half of the remaining bars to her coworkers. If no other bars were sold, what fraction of Conall's original 36 bars remained unsold? A 5/8 b 11/36 c 1/3 d 13/36 e 7/18 Answer by colliefan(239)   (Show Source): You can put this solution on YOUR website!The total number of candy bars to start with becomes the denominator of the ratio. That is 36. The numerator will be the total number of candy bars left. After he sold 10, 36-10 or 26 bars were left. If his mom sold half of 26, she sold 13 and 13 bars remain. The ratio is then: 13/36.