SOLUTION: How many liters of 30% alcohol solution and 80% alcohol solution must be mixed to obtain 100 liters of 50% alcohol solution?
Algebra.Com
Question 271748: How many liters of 30% alcohol solution and 80% alcohol solution must be mixed to obtain 100 liters of 50% alcohol solution?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
(liters of alcohol in final solution)/(liters of final solution) = 50%
Let = liters of 30% solution to use
Let = liters of 80% solution to use
given:
= liters of alcohol in 30% solution
= liters of alcohol in 80% solution
-----------------------------------------------
(1)
(2)
from (1)
(1)
(1)
Multiply both sides of (2) by
and subtract from (1)
(1)
(2)
and, from (2)
60 liters of the 30% solution and 40 liters
of the 80% solution are needed
check:
(1)
OK
RELATED QUESTIONS
How many liters of 80% alcohol solution and 40% alcohol solution must be mixed to obtain... (answered by ikleyn)
How many liters of 80% alcohol solution and 20% alcohol solution must be mixed to obtain... (answered by richwmiller)
How many liters of 50% alcohol solution and 20% alcohol solution must be mixed to obtain... (answered by Alan3354)
How many liters of 80% alcohol solution and 20% alcohol solution must be mixed to obtain... (answered by checkley79)
How many liters of 80% alcohol solution and 20% alcohol solution must be mixed to obtain... (answered by josmiceli)
how many liters of 20% alcohol solution and 10% alcohol solution must be mixed to obtain... (answered by nyc_function)
How many liters of 20% alcohol solution and 10% alcohol solution must be mixed to obtain... (answered by checkley77)
how many liters of 20% alcohol solution and 10% alcohol solution must be mixed to obtain... (answered by Fombitz)
How many liters of 60% alcohol solution and 20% alcohol solution must be mixed to obtain... (answered by richwmiller)