SOLUTION: The ratio of Aldo's cycling speed to Jose cycling speed is 6:5. Jose leaves school at 3pm and Aldo leaves at 3:10pm. By 3:30pm Aldo is only 2km behind Jose. How fast is each cycl

Question 260357: The ratio of Aldo's cycling speed to Jose cycling speed is 6:5. Jose leaves school at 3pm and Aldo leaves at 3:10pm. By 3:30pm Aldo is only 2km behind Jose. How fast is each cycling?
Found 2 solutions by richwmiller, ankor@dixie-net.com:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
a/j=6/5
30 minutes is 1/2 hr
20 minutes is 1/3 hr
a*(1/3)+2=j*(1/2)
a=24 j=20
24/20=6/5=a/j
24*1/3+2=20/2
10=10

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The ratio of Aldo's cycling speed to Jose cycling speed is 6:5.
Jose leaves school at 3pm and Aldo leaves at 3:10pm.
By 3:30pm Aldo is only 2km behind Jose. How fast is each cycling?
:
Let x = the multiplier
then
6x = A's speed
and
5x = J's speed
:
At 3:30
30 min = J's travel time, which is hr
20 min = A's travel time, which is hr
:
Write a distance equation: Dist = speed * time
:
J's dist - A's dist = 2 km
(5x) - (6x) = 2
Multiply equation by 6 to get rid of the denominators, results
3(5x) - 2(6x) = 6(2)
:
15x - 12x = 12
:
3x = 12
x =
x = 4 is the multiplier
:
6*4 = 24 km/hr is A's speed
5*4 = 20 km/hr is J's speed
:
:
Check solution by finding the distance each traveled
A: * 24 = 8 km
J: * 20 = 10 km; 2km difference

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