SOLUTION: Thirty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to ten percent salt?

Question 252759: Thirty pounds of a salt-water solution contains fifteen percent salt. How much water must be added to weaken the solution to ten percent salt?
Found 2 solutions by hokies, richwmiller:
Answer by hokies(65) (Show Source): You can put this solution on YOUR website!
30*.15 = (30+x)*.1
salt before adding water = salt after adding water
(30 pounds)*(15 percent salt) = (30+x pounds)*(10 percent salt)
Solve this equation for x: x = 15 pounds
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
.15*30+0*x=(30+x)*.10
x=15

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