SOLUTION: What weight of an alloy containing 10% silver must be melted with an alloy containing 60% silver to obtain 10 lb of an alloy containing 40% silver?
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Question 222478: What weight of an alloy containing 10% silver must be melted with an alloy containing 60% silver to obtain 10 lb of an alloy containing 40% silver?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What weight of an alloy containing 10% silver must be melted with an alloy containing 60% silver to obtain 10 lb of an alloy containing 40% silver?
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Equation:
silver + silver = silver
0.10x + 0.60(10-x) = 0.40(10)
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Multiply thru by 100 to get:
10x + 60*10 - 60x = 40*10
-50x = -20*10
x = 4 lbs. (amount of 10% alloy needed for the mixture)
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Cheers,
Stan H.
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