SOLUTION: a boy is 8 years older than his siter in ten years time, the ratio of their ages will be 3:2.what is the boys present age.

Question 187187: a boy is 8 years older than his siter in ten years time, the ratio of their ages will be 3:2.what is the boys present age.

Answer by uday1435(57) (Show Source): You can put this solution on YOUR website!
Let the boy is b years and his sister s years
Given b = s + 8 ---- eqn (1)
After 10 years boy�s age = b+10 and his sister�s age = s+10
Given (b+10)/(s+10) = 3/2
Cross multiplying we get
2(b+10) = 3(s+10)
2b + 20 = 3s + 30
2b � 3s = 10 plugging in the value of b from eqn(1) we get
2(s+8) � 3s = 10
2s + 16 � 3s = 10
So - s = - 6 therefore the sister is 6 years old and the boy is( 6+8 )= 14 years old

If you still require further clarifications please write to udayakumar.t.r@gmail.com

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