SOLUTION: Three tennis balls are tightly packed in a can.(circular cylinder). What fraction of the volume of the can is occupied by the tennis balls?
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Question 183334: Three tennis balls are tightly packed in a can.(circular cylinder). What fraction of the volume of the can is occupied by the tennis balls?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Three tennis balls are tightly packed in a can.(circular cylinder). What fraction of the volume of the can is occupied by the tennis balls?
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Volume of each ball is (4/3)pi*r^3
Total ball volume = 3(4/3)pi*r^3 = (4*pi*r^3)
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Volume of the can:
Area of the base = pi*r^2
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Height of the can = 6r
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Volume of the can 6r*pir^2 = 6pir^3
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Desired Fraction: 6pir^3/4pir^3 = 3/2
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Cheers,
Stan H.
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