SOLUTION: A chemist needs 10 L of a 50% alcohol solution. She must mix a 40% solution and a 65% solution. How many liters of each required to obtain what she needs?

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 Question 181436: A chemist needs 10 L of a 50% alcohol solution. She must mix a 40% solution and a 65% solution. How many liters of each required to obtain what she needs?Answer by stanbon(57387)   (Show Source): You can put this solution on YOUR website!A chemist needs 10 L of a 50% alcohol solution. She must mix a 40% solution and a 65% solution. How many liters of each required to obtain what she needs? ---------------------------------------------------- Equation: alcohol + alcohol = alcohol 0.40x + 0.65(10-x) = 0.50*10 Multiply thru by 100 to get: 40x + 65(10-x) = 50*10 40x + 650 - 65x = 500 -25x = -150 x = 6 L (amt. of 40% solution in the mixture) 10-x = 4 L (amt. of 65% solution in the mixture) ================================================================ Cheers Stan H.