SOLUTION: What quantity of 80% solution must be mixed with a 30% solution to produce 750 mL of a 50% solution?

Question 163030: What quantity of 80% solution must be mixed with a 30% solution to produce 750 mL of a 50% solution?
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!

Take note of the following:
80% solt'n="x"
30% solt'n="y"
So, -------------------------------> EQN 1
In EQN 1 we get, --------------------> EQN 2
After the mixture,
---------------------> EQN 3
Subst. EQN 2 in EQN 3:

----->
, QUANTITY for the 30% solt'n.
Via EQN 2,

, QUANTITY for the 80% solt'n.
In doubt? Go back EQN 3,

Thank you,
Jojo
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