SOLUTION: Can you please help me with this word problem? Thank you Stella's Sweet Shoppe ordered jelly beans from two different distributors at different prices. Stella wants to combine t

Question 161004This question is from textbook intermediate algebra
: Can you please help me with this word problem? Thank you
Stella's Sweet Shoppe ordered jelly beans from two different distributors at different prices. Stella wants to combine the two types of jelly beans to make a mixture that costs $2.10 per pound. How many pounds of jelly beans that cost $1.40 per pound should be mixed with 7 pounds of jelly beans that cost $2.40 per pound to obtain the desired mixture? This question is from textbook intermediate algebra

Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=amount of $1.40 jelly beans needed
Value of the $1.40 beans=$1.40x
Value of the $2.40 beans=$2.40(7)
Value of the final mixture=$2.10(7+x)
Now we know that the value of the beans before they are mixed together has to equal the value of the beans after they are mixed together, so:
$1.40x+$2.40*7=$2.10(7+x) get rid of parens (distributive law)
$1.40x+$16.80=$14.70+$2.10x subtract $14.70 and also $1.40x from each side
$1.40x-$1.40x+$16.80-$14.70=$14.70-$14.70+$2.10x-$1.40x collect like terms
$2.10=$0.70x divide each side by $0.60
x=3 lbs-------------amount of $1.40 jelly beans needed
CK
$1.40*3+$2.40*7=$2.10*10
$4.20+$16.80=$21.00
$21.00=$21.00
Hope this helps--ptaylor

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