# SOLUTION: mary invests \$24,000 in two seperate accounts. one earns 6% simple interest and the other 9%. if she earned a total of \$1740, how much did she invest at each rte?

Algebra ->  Algebra  -> Percentage-and-ratio-word-problems -> SOLUTION: mary invests \$24,000 in two seperate accounts. one earns 6% simple interest and the other 9%. if she earned a total of \$1740, how much did she invest at each rte?      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Word Problems: Problems on percentages, ratios, and fractions Solvers Lessons Answers archive Quiz In Depth

 Question 160297: mary invests \$24,000 in two seperate accounts. one earns 6% simple interest and the other 9%. if she earned a total of \$1740, how much did she invest at each rte?Answer by jojo14344(1512)   (Show Source): You can put this solution on YOUR website! Let "x", amount invested at 9%. So "24000-x" is the amount inv. at 6%. Putting into eqn: working eqn --------------> amt invested at 9% -----> amt invested at 6% check via working eqn: Thank you, Jojo