SOLUTION: 1. The cost, in millions of dollars, to remove x % of pollution in a lake modeled by C= 6,000 / 200-2x a. What is the cost to remove 75% of the pollutant? b. What is the cost

Question 158318: 1. The cost, in millions of dollars, to remove x % of pollution in a lake modeled by C= 6,000 / 200-2x
a. What is the cost to remove 75% of the pollutant?
b. What is the cost to remove 90 % of the pollutant?
c. What is the cost to remove 99% of the pollutant?
d. For what value is this equation undefined?
e. Do the answers to sections a�d match your expectations? Why or why not?

Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
C=6,000/200-2x
C=30-2*.75
C=30-1.5
C=$28.5 MILLION FOR 75% REMOVAL.
C=30-2*.90
C=30-1.8
C=$28.2 MILLION FOR 90% REMOVAL.
C=30-2*.99
C=30-1.98
C=$28.02 MILLION FOR 99% REMOVAL.
ALL % YIELD DEFINED ANSWERS.
INCREASE IN % REMOVAL SHOULD INCREASE NOT DECREASE COSTS.

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