SOLUTION: can someone please help me solve this problem?
2. A business invests $10,000 in a savings account for two years. At the beginning of the second year, an additional $3500 is inves
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Question 154601This question is from textbook elementary and intermediate algebra concepts and applications
: can someone please help me solve this problem?
2. A business invests $10,000 in a savings account for two years. At the beginning of the second year, an additional $3500 is invested. At the end of the second year, the account balance is $15,569.75. What was the annual interest rate?
This question is from textbook elementary and intermediate algebra concepts and applications
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
end of 1st yr __ 10000(1+r)
end of 2nd yr __ [10000(1+r)+3500](1+r)=15569.75
10000+10000r+3500+10000r+10000r^2+3500r=15569.75 __ subtracting 15569.75 __ 10000r^2+23500r-2069.75=0
use quadratic formula to find r
r=8.5%
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