You can
put this solution on YOUR website!First he gives x/2+2 (he has after that x/2-2)
he gives then (x/2-2)/2+2=x/4+1 (he has after that x/4-3)
he gives then (x/4-3)/2+2=x/8+1/2 (he has after that x/8-7/2
then x/8-7/2=1
then x/8=9/2
x=36
check:
gives 0.5(36)+2=20 then he has 16
gives 0.5(16)+2=10 then he has 6
gives 0.5(6)+2=5 then he has only 1 plant
You can
put this solution on YOUR website!GOOD!!!!! YOU GAVE IT A SHOT
WHEN THE GUARD GIVES, YOU NEED TO KEEP TRACK OF WHAT HE HAS LEFT.
OK I FIND IT EASIER TO WORK THESE WORD PROBLEMS IF I CLEARLY LAY OUT WHAT THE UNKNOWNS REPRESENT, SO:
Let x= the number of plants originally stolen
The thief gives (x/2)+2 plants to the first guard
Thief then has x-((x/2)+2) or 2x/2-(x/2)-2 =(x/2)-2 plants left
Thief gives 1/2((x/2-2)+2) or (x/4)-1+2=(x/4)+1 to second guard
Thief then has ((x/2)-2)-((x/4)+1) or (x/2)-2-(x/4)-1=(x/4)-3 plants left
Thief gives 1/2((x/4)-3)+2 or (x/8)-(3/2)+2=(x/8)+1/2 to third guard
Thief has left ((x/4)-3)-((x/8)+1/2) and we are told that this equals 1, so:
(x/4)-3-(x/8)-1/2=1 multiply each term by 8
2x-24-x-4=8 simplify
x-28=8 add 28 to both sides
x-28+28=8+28
x=36-----------------number of pLAnts originally stolen
Ck
First guard
Gives 1/2(36)+2=18+2=20
Has left 36-20=16
Second guard
Gives 1/2(16)+2=10
Has left 16-10=6
Third guard
Gives 1/2(6)+2=5
Has left 6-5=1
Hope this helps----ptaylor
You can
put this solution on YOUR website!THE EQUATION SHOULD BE:
X-(X/2+2)-(X/4+2)-(X/8+2)=1
YOU SHOULD START WITH THE TOTAL NUMBER OF PLANTS STOLEN WHICH IS X.
X-X/2-2-X/4-2-X/8-2=1
X-X/2-X/4-X/8=1+2+2+2 NOW COMBINE THE X TERMS USING A COMMON DENOMINATOR OF 8
(8X-4X-2X-1X)/8=7
X/8=7 NOW CRIOSS MULTIPLY
X=7*8
X=56 ANSWER FOR THE NUMBER OF PLANTS STOLEN.
PROOF:
56-(56/2=2)-(56/4+2)-(56/8+2)=1
56-28-2-14-2-7-2=1
56-55=1
1=1