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A donut shop sold 3/5 of their glazed donuts in the morning.
In the afternoon, they sold 5/6 of the remaining glazed donuts.
The ratio of the remaining glazed donuts to the remaining chocolate donuts was 2:7.
If they had 42 chocolate donuts left, how many total donuts (glazed + chocolate) did the shop have
at the very beginning?
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Let 'x' be the number of glazed donuts in the chop at the very beginning.
Let 'c' be the number of remaining chocolate donuts, which number is mentioned in the problem: c = 42.
In the morning the shop sold of their glazed donuts.
Hence, glazed donuts remained.
Of this glazed donuts, were sold afternoon.
So, = glazed donuts were sold afternoon.
Thus + = = glazed donuts
were sold during the day, and glazed donut remained at the evening.
From the condition, we can write
= , or = ,
which gives
x = .
Substitute here c= 42 to get
x = = 2*15*6 = 180.
So, the starting number of the glazed donuts was 180 at the very beginning.
It is what we can get from the given problem, using all given information.
But we have no any other data to determine the number of the chocolate donuts at the very beginning.
So, in the given form, the problem is DEFECTIVE and does not allow to answer the posed question.
Analyzed as far as it is possible with explanation WHY the problem is FAULT.