SOLUTION: What is the equation in slope-intercept form of the line that passes through the point (5, 0) and is parallel to the line represented by y = 1.2x + 3.8? A. y = 1.2x

SOLUTION: What is the equation in slope-intercept form of the line that passes through the point (5, 0) and is parallel to the line represented by y = 1.2x + 3.8? A. y = 1.2x - 6 B. y

Question 1206809: What is the equation in slope-intercept form of the line that passes through the point (5, 0) and is parallel to the line represented by y = 1.2x + 3.8?
A. y = 1.2x - 6
B. y = -1.2x + 6
C. y = 1.2x + 5
D. y = -1.2x - 5
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
general equation is y = mx + b
m is the slope
b is the y-intercept.

if the line is parallel, it has the same slope, so the equation for that line becomes y = 1.2 + b.

if the line passes through the point (5,0), then x-coordinate is 5 and y-coordinate is 0.

replace y with 0 and x with 5 in the equation to get:

0 = 1.2 * 5 + b

solve for b to get b = -6.

equation of the line parallel to the given line and passing through the point (5,0) is y = 1.2x - 6.

here's what both lines look like on a graph.

you can see that the lines are parallel because the vertical distance between the lines is the same at x = 0 and x = 5.
that would be 9.8 in both cases.

at x = 0, the difference in y is 3.8 - -6 = 3.8 + 6 = 9.8
at x = 5, the difference in y is 9.8 - 0 = 9.8
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