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Cassy Finance Company has a total of N$20 million earmarked for home loans and automobile loans.
On average, home loans will have a 10% rate of return on the loans given out while automobile
loans will yield a 12% rate of return on the loans extended. Management has also stipulated that the
total amount of home loans should be at least four times the total amount of automobile loans. Use
the graphical method to determine the total amount of loans the company should extend to each of
the two categories of customers in order to maximize the rate of return on the loans extended
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Let x be the (total) amount of the automobile loans.
Let y be the (total) amount of the home loans.
One restriction is
y >= 4x (1)
Another restriction is
x + y = 20 millions dollars. (2)
The return rate of the mixture of these loans is
R(x,y) = (dimensionless quantity) (3)
There are also standard non-negativity restrictions x >= 0, y>= 0. (4)
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| The problem wants we find the maximum R(x,y) under given restrictions. |
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Let's simplify the expression for R(X,y).
For it, we express y = 20-x from (2) and substitute it into (3). We get then R(x,y) as the function of x, ONLY:
R(x) = = = = 0.001x + 0.1.
So, R(x) is a linear function of x. It will facilitate finding the maximum GREATLY.
Now we should determine, on which set of real numbers {x} we should look for the maximum of R(x).
To determine it, substitute y = 20-x into (1). You will get
20-x >= 4x, or 20 >= 4x + x, or 20 >= 5x, or x <= 20/5 = 4.
Thus the set of {x}, where we look for the maximum of R(x) is 0 <= x <= 4.
Now, function R(x) = 0.001x + 0.1 is a linear monotonically increasing function,
and, for given set of {x}, it gets the maximum at the end-point x = 4 (which is OBVIOUS) .
The value of the maximum is then = R(4) = 0.001*4 + 0.1 = 0.104.
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| So, under given restrictions, the company should extend |
| 4 millions dollars to automobile loans and 16 million dollars to home loans. |
| The maximum return rate is then 0.104 = 10.4%. |
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It is the ANSWER, and the problem is just solved.