SOLUTION: The width of a rectangle is 15 less than twice its length. If the perimeter of the rectangle is 30 feet, what are the dimensions?

Question 1194662: The width of a rectangle is 15 less than twice its length. If the perimeter of the rectangle is 30 feet, what are the dimensions?
Found 3 solutions by MathLover1, josgarithmetic, MathTherapy:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

The width of a rectangle is less than twice its length .

If the perimeter of the rectangle is feet, we have
...substitute

no find the width

so, the dimensions are:
length is
width is

Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
These will all work the same no matter what the given values, if the values are meaningful.

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The width of a rectangle is k less than r times its length, L. If the perimeter of the rectangle is p feet, what are the dimensions?
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Dimensions,
L, length
rL-k, width
-
p, perimeter
UNKNOWN VARIABLE, L

and you can plug in the given values and compute L.

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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

The width of a rectangle is 15 less than twice its length. If the perimeter of the rectangle is 30 feet, what are the dimensions?

With L being length, width = 2L - 15

Length or
You should now be able to find width, and you'll then have the dimensions (length & width).
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