SOLUTION: In a survey of local residents, 1/5 were left-handed and
1/12 were ambidextrous. The rest were right-handed.
What is the ratio of right-handed people to everyone else?
A) 29/37
Algebra.Com
Question 1190227: In a survey of local residents, 1/5 were left-handed and
1/12 were ambidextrous. The rest were right-handed.
What is the ratio of right-handed people to everyone else?
A) 29/37
B) 34/47
C) 39/65
D) 43/17
E) 40/19
Answer by math_tutor2020(3817) (Show Source): You can put this solution on YOUR website!
Answer: D) 43/17
Reasoning:
The denominators are 5 and 12, which multiply to 5*12 = 60. This is a common denominator. I'll pick this number as the total number being surveyed.
If we had 60 residents, then,
1/5 * 60 = 12 are left-handed
1/12 * 60 = 5 are ambidextrous
That leaves
60-12-5 = 43 are right-handed
43 people are right-handed, and 60-43 = 17 are not right-handed (or note that 12+5 = 17)
The ratio of right-handers vs everyone else is 43/17
We can write that as 43:17 which is practically identical notation and means the same exact thing.
The ratio cannot be reduced further because 43 and 17 have no factors in common other than 1.
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