SOLUTION: A jar contains red, white, and yellow candy pieces in the ratio 9:5:4 of respectively. When 7 pieces of red candy and 5 pieces of white candy are removed from the jar and 3 p

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Question 1189278: A jar contains red, white, and yellow candy pieces
in the ratio 9:5:4 of respectively. When 7 pieces of red
candy and 5 pieces of white candy are removed
from the jar and 3 pieces of yellow candy are added,
the ratio of red to white to yellow becomes 4: 2: 3.
If the jar contains only these three colors of candy,
how many pieces were originally in the jar?

Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.
A jar contains red, white, and yellow candy pieces
in the ratio 9:5:4 of respectively. When 7 pieces of red
candy and 5 pieces of white candy are removed
from the jar and 3 pieces of yellow candy are added,
the ratio of red to white to yellow becomes 4: 2: 3.
If the jar contains only these three colors of candy,
how many pieces were originally in the jar?
~~~~~~~~~~~~~~~~~~

From the condition, we can write

    R = 9x,  W = 5x,  Y = 4x

for the number of red, white and yellow candy pieces in the jar originally,
where x is the common factor (multiplier).


According to the condition, we have this proportion

     =  = 2,

which gives

    9x - 7 = 2*(5x-5)

    9x - 7 = 10x - 10

    10 - 7 = 10x - 9x

       x = 3.


At this point, we can just answer the problem's question: R = 27,  W = 15,  Y = 12.


The last condition is EXCESSIVE, and we should check that it does not contradict to 
(is consistent with) the answer.


CHECK.  After manipulations, the jar contains  R = 20,  W = 10  and Y = 15 candy pieces,

       so this proportionality  4 : 2 : 3  is held for the final state.

Solved and explained.



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