SOLUTION: Dominic, Erica and Francis received a sum of money in the ratio 3:1:8. When Francis gave Erica half of his money and Dominic gave $8 to Erica, the ratio of the amount of money Domi

Question 1184561: Dominic, Erica and Francis received a sum of money in the ratio 3:1:8. When Francis gave Erica half of his money and Dominic gave $8 to Erica, the ratio of the amount of money Dominic had to the amount of money Erica had to the amount of money Francis had became 1:3:2. How much money did the three of them receive altogether?

(1) $24
(2) $48
(3) $88
(4) $96
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Using x as a common factor to relate ratios for the three

Dominic  :  Erika   :   Francis
  3x          x          8x

The described transfers of moneys made this:

Dominic  :  Erika   :   Francis
3x-8        x+4x+8       8x-4x
3x-8     :  5x+8    :    4x
 1      :     3     :     2

Equation can be setup, .

Solve and see .
This says that ratio up to the actual money each started with:
Dominic:Erika:Francis is 24:8:64.
.
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