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A fund-raising project lasted 2 weeks.
In the 1st week, Team Cupcakes raised 4/7 as much as money as Team Drinks.
In the 2nd week, Team Cupcakes raised another $214 while Team Drinks raised another $260.
The total amount raised by Team Cupcakes was 2/3 as much as the total amount raised by Team Drinks.
What was the total amount of money raised by the two teams?
I not yet learnt algebra. Please help me to solve this problem
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This problem is NOT INTENDED for those who " not yet learnt algebra ".
THEREFORE, I will IGNORE your note saying that you did not learn algebra, yet.
I will solve it as if I communicate with a person who is able to understand the subject.
If you do not understand - - - then it is YOUR problem - not mine.
If not you, then next generations of students will learn from my solution, reading it in the future from the archive.
For short, I will call the teams by letters " C " and " D ".
Since "The total amount raised by Team C was 2/3 as much as the total amount raised by Team D",
I will assume that total amount raised by D was 3x dollars, while the total amount raised by C was 2x dollars.
Then
the team D's raising in the 1st week is 3x - 260 dollars, while
the team C's raising in the 1st week is 2x - 214 dollars.
Based on problem's condition, we have this equation
2x - 214 = .
To solve this equation, multiply both sides by 7, then simplify.
14x - 7*214 = 12x - 4*260
14x - 12x = 7*214 - 4*260
2x = 458.
x = 458/2 = 229.
The total amount of money raised by the two teams is then 2x + 3x = 5x = 5*229 = 1145 dollars. ANSWER
Solved.