SOLUTION: Henry spent 1/4 of his money and an additional $3 on a number of DVDs. He then spent 3/5 of the remaining money and an additional $6 on a number of batteries. Given that he was lef

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Henry spent 1/4 of his money and an additional $3 on a number of DVDs. He then spent 3/5 of the remaining money and an additional $6 on a number of batteries. Given that he was lef      Log On


   



Question 1184436: Henry spent 1/4 of his money and an additional $3 on a number of DVDs. He then spent 3/5 of the remaining money and an additional $6 on a number of batteries. Given that he was left with $24, how much money did Henry have at first?
Answer by ikleyn(52797) About Me  (Show Source):
You can put this solution on YOUR website!
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Henry spent 1/4 of his money and an additional $3 on a number of DVDs.
He then spent 3/5 of the remaining money and an additional $6 on a number of batteries.
Given that he was left with $24, how much money did Henry have at first?
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            It is a nice problem to be solved backward and explained accordingly.


First, let x be the remainder money amount after buying a number of DVDs.


Then for this amount of money you have this equation

    x - %28%283%2F5%29x+%2B+6%29 = 24.     (1)


To solve it, multiply everything in equation (1) by 5  to get

    5x - (3x + 30) = 24*5

    5x - 3x        = 24*5 + 30

       2x          = 120 + 30 = 150

        x                     = 150/2 = 75.


Thus you found that after buying a number of DVDs, the remainder was 75 dollars.


OK.     It gives you  NEXT EQUATION from the first part of the problem 

    M - %28%281%2F4%29M+%2B+3%29 = 75    (2)


where M is the unknown money amount Henry had at first.


From this equation, you get

    %283%2F4%29M = 75 + 3 = 78,

        M    = %2878%2A4%2F3%29 = 26*4 = 104.


ANSWER.  At first,  Henry had $104.

Solved and thoroughly explained.

Check my answer on your own.