SOLUTION: 3/4 of Nancy’s money is equal to 2/5 of Irene’s money. The difference in their amount of money is equal to 1/7 of Ellen’s money. Given that Ellen has $340 more than Irene,

Question 1184114: 3/4 of Nancy’s money is equal to 2/5 of Irene’s money. The difference in their amount of
money is equal to 1/7 of Ellen’s money. Given that Ellen has $340 more than Irene, find the
total sum of money that the 3 girls have altogether.
Answer by ikleyn(52824) (Show Source): You can put this solution on YOUR website!
.
3/4 of Nancy’s money is equal to 2/5 of Irene’s money. The difference in their amount of
money is equal to 1/7 of Ellen’s money. Given that Ellen has $340 more than Irene, find the
total sum of money that the 3 girls have altogether.
~~~~~~~~~~~~~~~~~

Let x be the amount Nancy had, in dollars.


We are given that  is equal to   of Irene's money; hence, Irene had  =   dollars.


The difference of their money (Irene and Nancy) is   - x = .


It is  of the Ellen's money;  hence, Ellen's money is   = .


The last condition of the problems gives this equation


    Ellen - Irene = 340 dollars,   or   -  = 340.


To solve, multiply all the terms by 8


    49x - 15x = 340*8

      34x     = 340*8

        x     = 10*8 = 80.


Thus Nancy had  $80;  Irene had   =  = $150;  Ellen had  =  = $490.


ANSWER.  The total is  80 + 150 + 490 = 720 dollars.

Solved.

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