SOLUTION: A piece of industrial machinery in the research and development lab of the company you work with, decreases in value every month after it was originally purchased for $96,852. An e

Question 1183040: A piece of industrial machinery in the research and development lab of the company you work with, decreases in value every month after it was originally purchased for $96,852. An equation that models the value of machinery as a function of time (in months) is as follows: V(t)=(Vo)(0.26^t)
What percentage of the previous months value, remains each month?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
the equation is v(t) = v(0) * .26 ^ t

based on this formula, i believe the remaining value each month will be 26% of the remaining value from the previous month.

here's a graph showing the value at the end of each month.

as you can see, the value of the machine drops very quickly in the first month and slows dramatically after about 5 months.

the remaining value each succeeding month is 26% of the value in the previous month.

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