SOLUTION: in 2015 the median age at first marriage of U.S. women (27.1) was what percent less than median age at first marriage of U.S. men (29.2 years)
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Question 1165330: in 2015 the median age at first marriage of U.S. women (27.1) was what percent less than median age at first marriage of U.S. men (29.2 years)
Answer by CPhill(2138) (Show Source): You can put this solution on YOUR website!
This is a percentage decrease calculation.
The formula for percentage less than (or percentage decrease) is:
$$\text{Percentage Less} = \frac{\text{Reference Value} - \text{Comparison Value}}{\text{Reference Value}} \times 100\%$$
In this case:
* Reference Value (Men's age) $= 29.2$ years
* Comparison Value (Women's age) $= 27.1$ years
$$\text{Percentage Less} = \frac{29.2 - 27.1}{29.2} \times 100\%$$
```python?code_reference&code_event_index=2
# Given values
men_age = 29.2
women_age = 27.1
# Calculate the percentage difference
percentage_less = ((men_age - women_age) / men_age) * 100
print(f"Percentage less: {percentage_less}")
```
```text?code_stdout&code_event_index=2
Percentage less: 7.191780821917801
```
The median age at first marriage of U.S. women (27.1 years) was approximately **7.19% less** than the median age for U.S. men (29.2 years) in 2015.
### Calculation Steps:
1. **Find the Difference:**
$$29.2 \text{ years} - 27.1 \text{ years} = 2.1 \text{ years}$$
2. **Calculate the Percentage Decrease (using the men's age as the reference):**
$$\text{Percentage Less} = \frac{\text{Difference}}{\text{Men's Age}} \times 100\%$$
$$\text{Percentage Less} = \frac{2.1}{29.2} \times 100\%$$
$$\text{Percentage Less} \approx 0.071917 \times 100\%$$
$$\mathbf{\approx 7.19\%}$$
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