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Let x = the weight of the large box; y be the weight of the small box.
Then from the condition, you have these two equations
4x + 8y = 197 (1)
2x + 3y = 83 (2)
Multiply equation (2) by 2 (both sides). Keep equation (1) as is
4x + 8y = 197 (1')
4x + 6y = 166 (2')
Subtract equation (2') from (1'). You will get
2y = 197 - 166 = 31;
y = 31/2 = 15.5.
Then from equation (2)
2x = 83 - 3*15.5 = 36.5
x = 36.5/2 = 18.25,
ANSWER. The large box weights 18.25 kg; the small box weights 15.5 kg.
Solved.
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You use very old source, where weight is measured in kilograms.
This practice was stopped in 60-es last century, when after changing the measurement system,
kilograms were replaced by newtons as the unit of force/weight.