SOLUTION: A number, 1/5 of that number, and one sixth of that number are added. The result is 82. What is the original number? (prealgebra)

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Question 1153238: A number, 1/5 of that number, and one sixth of that number are added. The result is 82. What is the original number? (prealgebra)
Found 3 solutions by josgarithmetic, MathLover1, MathTherapy:
Answer by josgarithmetic(39620)   (Show Source): You can put this solution on YOUR website!
X, the number


.
.
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

let a number be
of that number is
of that number is
if they are added, we have
if the result is , we have
to find the original number, solve


.....both sides multiply by



=> exact solution

check:







Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
A number, 1/5 of that number, and one sixth of that number are added. The result is 82. What is the original number? (prealgebra)
Algebra:        With number being N, equation to be solved: 

Pre-Algebra:    

                The number, with the same denominator as the above fraction, is represented by 1, or fraction   

                We now see that: , and so, the number MUST BE: 

IGNORE the OTHER PERSON'S RESPONSE, as it is SENSELESS!! 

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