SOLUTION: What amount of a 15% HCL acid solution must be mixed with a 20% HCL acid solution to obtain 50 milliliters of 18% solution?

Question 1144784: What amount of a 15% HCL acid solution must be mixed with a 20% HCL acid solution to obtain 50 milliliters of 18% solution?
Answer by ikleyn(52787) (Show Source): You can put this solution on YOUR website!
.

Let x be the amount of the 15% solution, in milliliters.

Then the amount of the 20% solution is 50-x milliliters.


The equation to find "x" is this


    0.15x + 0.20*(50-x) = 0.18*50.


It says that the amount of the pure acid HCl in the mixture is the sum of the amounts of the pure acid HCl in the ingredients.


Express x from the equation and calculate


    x =  = 20 milliliters.    ANSWER

Solved.

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It is a standard and typical mixture problem.

For introductory lessons covering various types of mixture word problems see
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Typical word problems on mixtures from the archive
in this site.

You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization, from very detailed to very short.

Read them and become an expert in solution mixture word problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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